Quadratic equations are a fundamental part of algebra that we encounter often in our mathematical journey. They form a paradigm for a wide array of problems that can be resolved using the same formulaic approach. A quadratic equation is a second-order polynomial equation with three constants, typically represented as ax^{2} + bx + c = 0. This simple yet powerful construct has extensive applications, from calculating areas and determining trajectories to designing parabolic antennas and modeling market trends.

Today, we will dive into the world of quadratic equations by tackling an intriguing problem: solving the equation 4x^{2} – 5x – 12 = 0. This equation might seem daunting at first glance, but fear not! By breaking it down step by step, we’ll transform this complex task into a comprehensible exercise. So, grab your pen, paper, and calculator – let’s embark on this mathematical adventure together!

## Understanding the Basics

Let’s dive into the world of quadratic equations, the heart of our discussion. A quadratic equation, in its simplest form, is a polynomial equation of the second degree. This implies that in the equation, the highest power of an unknown variable, commonly denoted as ‘x’, is two. These equations are fundamental in mathematics and have wide-ranging implications from physics to engineering, finance, and even sports!

Now, let’s look at the standard form of a quadratic equation. It is generally represented as ax^{2} +bx +c = 0. In this equation, ‘a’, ‘b’, and ‘c’ are constants, and ‘x’ is the variable we are trying to solve for. The constant ‘a’ can’t be zero; if it were, the equation would no longer be quadratic but linear instead.

The term with the highest power (ax^{2}) is the quadratic term, bx is the linear term, and c is the constant term. Each term plays a unique role in shaping the graph of the equation and determining the solutions. The coefficients ‘a’ and ‘b’, along with the constant ‘c’, give the quadratic equation its unique characteristics and affect where it intersects the x-axis – these intersection points are the solutions we’re after!

In our specific equation, 4x^{2} – 5x – 12 = 0, ‘4’ is the coefficient of the quadratic term, ‘-5’ is the coefficient of the linear term, and ‘-12’ is the constant. Together, they shape the problem we need to solve. In the upcoming sections, we’ll apply this newfound knowledge to understand why we solve quadratic equations and how to use the quadratic formula to find the solutions to our equations.

## Why Solve Quadratic Equations?

At first glance, quadratic equations might seem like just another mathematical concept to wrap your head around. However, they hold a significant place in our everyday life and numerous scientific fields. Understanding and solving quadratic equations is more than just academic exercise, it’s a key to unlocking real-world problems.

### The Importance of Solving Quadratic Equations

Quadratic equations are everywhere. They provide a tool to model and solve a variety of problems across multiple disciplines including physics, engineering, business, and even medicine. For instance, in physics, quadratic equations can be used to calculate the trajectory of an object under the force of gravity. In business, they can help in optimizing profit and loss scenarios. Hence, being able to solve these equations equips us with a valuable skill set to understand and solve complex issues.

### Real-world Applications of Quadratic Equations

Let’s dive deeper into some specific examples where quadratic equations come into play.

**Physics:**One of the fundamental laws of motion, formulated by Sir Isaac Newton, states that the height (h) of an object in free fall after a certain time (t) is given by h = 1/2gt^2, where g is the acceleration due to gravity. This is a quadratic equation, and solving it can tell us how high the object will be at any point in time.**Engineering:**Engineers often use quadratic equations to calculate materials’ stress and strain, helping them design structures that can withstand specific pressures and forces.**Business:**Quadratic equations can also be useful in business for cost and revenue analysis. For example, a company might know that its profit (P) after selling x units of a product is given by P = ax^2 + bx + c, which is a quadratic equation. Solving this equation can help determine the number of units that need to be sold to maximize the profit.

In each of these examples, quadratic equations serve as an essential tool to model and solve problems. By understanding and being able to solve these types of equations, we open up a world of possibilities for problem-solving in various professional fields and everyday scenarios.

## The Quadratic Formula

Now, let’s dive into the heart of this equation-solving endeavor – the quadratic formula. This mathematical tool is a powerful ally when tackling quadratic equations, allowing us to find solutions with relative ease.

### What is the Quadratic Formula?

The quadratic formula is a universal solution for any quadratic equation in the standard form ax^{2} + bx + c = 0. It looks like this: x = [-b ± sqrt(b^{2} – 4ac)] / (2a). At first glance, it may seem a bit intimidating, but don’t worry! Let’s break it down piece by piece.

- ‘a’, ‘b’, and ‘c’ are coefficients from our quadratic equation.
- ‘sqrt’ refers to the square root, which is a mathematical operation that finds a number that, when multiplied by itself, gives the original number.
- The ‘±’ symbol means that there will be two solutions for ‘x’, one using addition and the other using subtraction.

### Applying the Quadratic Formula to Solve Equations

So how does this formula help us solve our quadratic equation? Simple! We just need to identify the values of a, ‘b’, and ‘c’ in our given equation, and substitute them into the formula. For example, in our equation 4x^{2} – 5x – 12 = 0, ‘a’ is 4, ‘b’ is -5, and ‘c’ is -12.

After substitution, we perform the operations in the formula sequentially. First, we calculate the value under the square root (known as the discriminant), then take the square root. Afterward, we add/subtract this value to/from -b, and finally divide by 2a to get the roots of the equation.

As you can see, the quadratic formula is a robust tool that can be used to unlock the solutions to any quadratic equation. All it requires is a bit of number crunching and careful application of the order of operations.

With this formula in hand, we’re ready to tackle the equation 4x^{2} – 5x – 12 = 0 in the next section, where we’ll go step-by-step through the solution process. So brace yourself, because clarity is just around the corner!

## Solving the Equation: Step-by-step Guide

Now that we’ve laid a solid foundation by understanding the basics of quadratic equations and the significance of the quadratic formula, let’s dive into the exciting part—solving our equation. The equation we are dealing with is *4x ^{2} – 5x – 12 = 0*.

### Identification of the values of a, b, and c

To start, we need to identify the coefficients in our equation. You’ll recall from our previous discussion that a standard quadratic equation takes the form *ax ^{2} + bx + c = 0*. Comparing this with our equation, it’s clear that ‘a’, the coefficient of x

^{2}, is 4; ‘b’, the coefficient of x, is -5; and ‘c’, the constant term, is -12.

### Application of the Quadratic Formula

With those values in hand, we’re ready to apply the quadratic formula, which is *x = [-b ± sqrt(b ^{2} – 4ac)] / (2a)*. We plug our values of a, b, and c into this formula to find the solutions for our equation.

### Detailed Step-by-step Walkthrough

Let’s break down the solution process step by step:

- First, we calculate the value inside the square root, known as the discriminant. Plugging our values into the formula, we get
*b*^{2}– 4ac = (-5)^{2}– 4*4*(-12) = 25 + 192 = 217. - Next, we calculate the two possible values for x using the quadratic formula. For the first value, we use the plus sign in the ± operator, and for the second value, we use the minus sign. This gives us:
*x*and_{1}= [5 + sqrt(217)] / (2*4) = 2.72 (approx.)*x*._{2}= [5 – sqrt(217)] / (2*4) = -1.22 (approx.)

We now have the two solutions to our equation: x = 2.72 and x = -1.22, approximately.

Remember, the reason we get two solutions is due to the nature of quadratic equations—they represent parabolas that can intersect the x-axis at two points. These intersection points correspond to our solutions. So there you have it, a step-by-step guide to solving our quadratic equation. Practice with these steps and soon they’ll become second nature!

## Verification of the Solution

So, we’ve arrived at our solutions using the quadratic formula. But how can we be certain that these solutions are correct? That’s where verification comes into the picture. One of the fundamental aspects of mathematical problem-solving is the practice of checking your answers. This step not only ensures accuracy but also deepens your understanding of the problem-solving process. Verification allows us to confidently assert the validity of our solutions and provides a convincing argument for others who may review our work.

### Why Verify?

Verifying the solution of an equation may seem like an extra, unnecessary step. After all, you’ve followed the procedure, and plugged in the numbers correctly, so why bother? The answer is simple: humans make mistakes. Even the most experienced mathematicians can slip up in their calculations. By verifying your solution, you’re double-checking your work, ensuring that no computational errors slip through.

Moreover, verification allows you to see the equation from another angle, reinforcing your understanding of the underlying mathematical principles. It’s a chance to reaffirm why your steps led to the correct solution.

### How to Verify?

The process of verification is straightforward. We substitute the obtained solutions back into the original equation and check whether both sides balance out. If they do, voila! You’ve verified your solution.

To put this into practice, let’s recall the quadratic equation we solved: 4x^{2} – 5x – 12 = 0, and suppose we found the solutions to be x1 and x2. Substituting x1 into the equation, we would obtain 4(x1)^{2} – 5(x1) – 12. If this simplifies to zero, then x1 is indeed a solution. We would follow the same process with x2.

This method of verification is a powerful tool to confirm the accuracy of your solutions and to help foster a deeper understanding of the equation and its solutions. So, next time you solve a quadratic equation, don’t skip the verification step! It’s your key to confidence, accuracy, and a deeper understanding of the wonderful world of mathematics.

## Conclusion

As we come to the end of this enlightening journey, it’s time to take a step back and revisit the steps we’ve taken to solve the quadratic equation 4x^{2} – 5x – 12 = 0. We started by understanding the basics where we acquainted ourselves with what a quadratic equation is and its standard form: ax^{2} + bx + c = 0. In our equation, ‘a’ represents the coefficient of x^{2}, which is 4, ‘b’ is the coefficient of x, which is -5, and ‘c’ is the constant term, -12.

We then delved into the importance of solving quadratic equations and their real-life applications, motivating us to learn this important skill. After that, we introduced the magic tool, the Quadratic Formula, which can be used to solve any quadratic equation. We identified the coefficients in our equation and substituted them into the formula, calculating the solutions step-by-step. Finally, we verified our solutions by substituting them back into the original equation, ensuring they satisfy it.

Now that you’ve walked through this process with us, you’re not just equipped with knowledge, but also a sense of accomplishment. Solving a quadratic equation might have seemed like a daunting task at first, but look at you now! You’ve joined the ranks of many who have turned their confusion into clarity.

But remember, like any other skill, mastering quadratic equations requires practice. Each equation you solve will add a new dimension to your understanding and make you more comfortable with the concept. So, don’t stop here. Dive into more problems, challenge yourself, and keep learning. With every problem you solve, you’re one step closer to becoming an expert.

So, keep practicing, keep exploring, and most importantly, keep enjoying the beauty of mathematics. Remember, the path from confusion to clarity is paved with perseverance and practice. As the famous mathematician Carl Friedrich Gauss once said, “Further, the dignity of the science itself seems to require that every possible means be explored for the solution of a problem so elegant and so celebrated.”

## Call-to-Action

We’ve navigated the intricate world of quadratic equations, uncovered the secrets of the quadratic formula, and successfully solved the equation 4x^{2} – 5x – 12 = 0. But this is just the beginning of your journey. Solving quadratic equations is a skill that takes practice to master, and each equation you solve only enhances your mathematical prowess. So, don’t stop here. Continue exploring, continue practicing, and continue challenging yourself with more complex quadratic equations.

Remember, every quadratic equation is a new puzzle waiting to be solved, a new challenge to overcome. These equations are not just abstract concepts; they have practical applications in various fields like physics, economics, engineering, and many more. So, by mastering these equations, you’re not just improving your math skills but also opening doors to numerous opportunities.

Now, you might be wondering where to go from here, and how to keep the momentum going. Well, there are numerous resources available both online and offline that can help you delve deeper into the fascinating world of quadratic equations. Websites such as Khan Academy, Coursera, and even YouTube offer comprehensive tutorials on quadratic equations. You can also refer to textbooks like “Algebra and Trigonometry” by Michael Sullivan or “Algebra: Structure and Method” by Richard G. Brown for a more detailed understanding.

Practicing problems is also a crucial part of learning. Try solving different types of quadratic equations, and challenge yourself with more complex problems. Websites like Brilliant.org, Mathway, and Wolfram Alpha provide a plethora of practice problems along with their solutions. This way, you can check your answers and understand where you went wrong, if at all.

On this exciting journey of exploration and learning, remember that it’s okay to make mistakes. They are stepping stones to success, providing valuable lessons and insights. So, embrace them, learn from them, and keep moving forward.